No one should doubt Beto O'Rourke's Progressive bona fides. Endorsements from Democracy for America (DFA) requires one to support poor and middle-class centric policies. It is clear our Democratic senatorial candidate has earned that backing.
Beto O'Rourke is the real deal. With his travails throughout 254 Texas counties, speaking to every Texan about his values, it is clear why DFA supports him. DFA Chair Jim Dean released the following statements.
"In 2018, Democrats have nominated a series of trailblazing warriors for inclusive populist priorities all across the country who will be positively critical to helping us seize the majority of the U.S. House and have a shot at retaking control of the Senate.
"Today, we're particularly excited to announce our endorsements of Beto O'Rourke for U.S. Senate in Texas."
Jim Dean continued.
"Beto O'Rourke (U.S. Senate - Texas) has distinguished himself this cycle not only by running one of the most impressive grassroots campaigns Texas has ever seen but by taking unequivocal, progressive stands on immigrant rights and racial justice. Beto O'Rourke's people-powered campaign and boldness have not only brought tens of thousands of new and frequently ignored voters into the political process, it's forced Ted Cruz, one of the most loathed fringe-right characters in Donald Trump's Washington swamp, into a single-digit race."
I interviewed Neil Sroka, Democracy for America (DFA) Director of communications at Netroots Nation 2018 where he said he expected solid Progressive performance at all levels in 2018.
"We've got some amazing candidates running for office," Neil Sroka said. "We are going to be supporting over 250 candidates throughout the country this year. And those are folks running from the tippy top of the ballot for U.S. Senate all the way down to county commissioner and water board member. There is so much to be excited about."
Beto O'Rourke talks Medicare for All
It is clear Beto O'Rourke became one of DFA's latest supported candidates. That speaks very well for his campaign.